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(B) The $As_2S_3$ sol is a negatively charged sol.According to the Hardy-Schulze rule,the coagulation power of an electrolyte depends on the valency o

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$I < III < II < IV$

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(B) The $As_2S_3$ sol is a negatively charged sol.According to the Hardy-Schulze rule,the coagulation power of an electrolyte depends on the valency of the coagulating ion (the ion with a charge opposite to that of the sol).For a negatively charged sol,the coagulating power depends on the charge of the cation.The cations present are:$(I) K_2SO_4 ightarrow K^+ 	ext{ (charge } +1)$$(II) CaCl_2 ightarrow Ca^{2+} 	ext{ (charge } +2)$$(III) Na_3PO_4 ightarrow Na^+ 	ext{ (charge } +1)$$(IV) AlCl_3 ightarrow Al^{3+} 	ext{ (charge } +3)$Comparing the charges: $K^+ = Na^+ Thus,the increasing order of coagulation power is $I = III < II < IV$.

Arrange the following electrolytes in the increasing order of coagulation power for the coagulation of $As_2S_3$ sol.
$\mathop {K_2SO_4}\limits_{(I)}$ $\mathop {CaCl_2}\limits_{(II)}$ $\mathop {Na_3PO_4}\limits_{(III)}$ $\mathop {AlCl_3}\limits_{(IV)}$

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Arrange the following electrolytes in the increasing order of coagulation power for the coagulation of $As_2S_3$ sol.$\mathop {K_2SO_4}\limits_{(I)}$ $\mathop {CaCl_2}\limits_{(II)}$ $\mathop {Na_3PO_4}\limits_{(III)}$ $\mathop {AlCl_3}\limits_{(IV)}$