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(D) The reactivity of a carbonyl compound towards nucleophilic addition depends on the electrophilicity of the carbonyl carbon.$1$. Steric hindrance:

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$III > I > IV > II$

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(D) The reactivity of a carbonyl compound towards nucleophilic addition depends on the electrophilicity of the carbonyl carbon.$1$. Steric hindrance: Smaller groups around the carbonyl carbon increase reactivity.$2$. Electronic effects: Electron-donating groups (like $-CH_3$) decrease the electrophilicity of the carbonyl carbon,while electron-withdrawing groups increase it.Comparing the compounds:$III$ $(HCHO)$ is formaldehyde,which has no electron-donating groups and minimal steric hindrance,making it the most reactive.$I$ $(CH_3CHO)$ is acetaldehyde,which has one electron-donating $-CH_3$ group.$IV$ $(CH_3COCH_3)$ is acetone,which has two electron-donating $-CH_3$ groups,making it less reactive than $I$.$II$ $(CH_3CONH_2)$ is an amide. The lone pair on the nitrogen atom is involved in resonance with the carbonyl group $(CH_3-C(=O)-NH_2 \leftrightarrow CH_3-C(-O^-)=N^+H_2)$,which significantly reduces the electrophilicity of the carbonyl carbon,making it the least reactive towards nucleophilic addition.Thus,the correct order of reactivity is $III > I > IV > II$.

Arrange the following compounds in the correct order of their reactivity towards nucleophilic addition reactions:
$I: CH_3CHO$
$II: CH_3CONH_2$
$III: HCHO$
$IV: CH_3COCH_3$

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Arrange the following compounds in the correct order of their reactivity towards nucleophilic addition reactions:$I: CH_3CHO$$II: CH_3CONH_2$$III: HCHO$$IV: CH_3COCH_3$