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(C) Nucleophilic addition reactivity depends on the electrophilicity of the carbonyl carbon and steric hindrance.$1.$ Aldehydes are generally more rea

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$II > III > I > IV$

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(C) Nucleophilic addition reactivity depends on the electrophilicity of the carbonyl carbon and steric hindrance.$1.$ Aldehydes are generally more reactive than ketones due to less steric hindrance and fewer electron-donating groups.$2.$ Electron-withdrawing groups (like $Cl$) increase the positive charge on the carbonyl carbon via the $-I$ effect,thereby increasing reactivity.Comparing the given compounds:- $(II)$ $ClCH_2CHO$ is an aldehyde with an electron-withdrawing group,making it the most reactive.- $(III)$ $HCHO$ is the simplest aldehyde with minimal steric hindrance.- $(I)$ $CH_3COCH_2Cl$ is a ketone with an electron-withdrawing group.- $(IV)$ $CH_3COCH_3$ is a simple ketone with two electron-donating methyl groups.Therefore,the order of decreasing reactivity is: $II > III > I > IV$.

Arrange the following compounds in order of decreasing reactivity for nucleophilic addition reaction:
$(I)$ $CH_3COCH_2Cl$
$(II)$ $ClCH_2CHO$
$(III)$ $HCHO$
$(IV)$ $CH_3COCH_3$

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Arrange the following compounds in order of decreasing reactivity for nucleophilic addition reaction:$(I)$ $CH_3COCH_2Cl$$(II)$ $ClCH_2CHO$$(III)$ $HCHO$$(IV)$ $CH_3COCH_3$