Arrange the anions (p) text{CH}_3^{-}, (q) te | vedclass

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Question

(A) The basic strength of anions is inversely proportional to the acidic strength of their conjugate acids.The conjugate acids are: $(p) 	ext{CH}_4,

Vedclass · Accepted Answer

$p > q > r > s$

Vedclass · Answer

(A) The basic strength of anions is inversely proportional to the acidic strength of their conjugate acids.The conjugate acids are: $(p) 	ext{CH}_4, (q) 	ext{NH}_3, (r) 	ext{H}_2	ext{O}, (s) 	ext{HF}$.The acidic strength order of these acids is: $	ext{HF} > 	ext{H}_2	ext{O} > 	ext{NH}_3 > 	ext{CH}_4$.Therefore,the basic strength order of their conjugate bases is: $	ext{CH}_3^{-} > 	ext{NH}_2^{-} > 	ext{OH}^{-} > 	ext{F}^{-}$,which corresponds to $p > q > r > s$.

Acid	$HF$	$HCl$	$HBr$	$HI$
$K_a$	$7.2 \times 10^{-4}$	$1 \times 10^6$	$1 \times 10^9$	$3 \times 10^{11}$

Arrange the anions $(p) \text{CH}_3^{-}, (q) \text{NH}_2^{-}, (r) \text{OH}^{-}, (s) \text{F}^{-}$ in decreasing order of their basic strength.

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