Arrange the acidity of the given four compoun | vedclass

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(B) The acidity of a compound depends on the stability of its conjugate base.$1.$ In $(I)$ $CH_3COCH_2COCH_3$ (acetylacetone),the protons on the centr

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$I > IV > II > III$

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(B) The acidity of a compound depends on the stability of its conjugate base.$1.$ In $(I)$ $CH_3COCH_2COCH_3$ (acetylacetone),the protons on the central carbon are highly acidic because the resulting carbanion is stabilized by resonance with two carbonyl groups (active methylene group).$2.$ In $(IV)$ $CH_3CHO$ (acetaldehyde) and $(II)$ $CH_3COCH_3$ (acetone),the $\alpha$-hydrogens are acidic due to resonance with one carbonyl group. Aldehydes are more acidic than ketones because the additional methyl group in ketones has an electron-donating $+I$ effect,which destabilizes the carbanion.$3.$ In $(III)$ $CH \equiv CH$ (acetylene),the hydrogen is attached to an $sp$ hybridized carbon,making it acidic,but it is significantly less acidic than the $\alpha$-hydrogens of carbonyl compounds.Therefore,the decreasing order of acidity is: $I > IV > II > III$.

List-$I$ (Chemical Reaction)	List-$II$ (Reagent used)
$(a)$ $CH_{3}COOCH_{2}CH_{3} \rightarrow CH_{3}CH_{2}OH$	$(i)$ $CH_{3}MgBr / H_{3}O^{+}$ ($1$ equivalent)
$(b)$ $CH_{3}COOCH_{3} \rightarrow CH_{3}CHO$	$(ii)$ $H_{2}SO_{4} / H_{2}O$
$(c)$ $CH_{3}C \equiv N \rightarrow CH_{3}CHO$	$(iii)$ $DIBAL-H / H_{2}O$
$(d)$ $CH_{3}C \equiv N \rightarrow CH_{3}COCH_{3}$	$(iv)$ $SnCl_{2}, HCl / H_{2}O$

Column-$I$ (Reactant)	Column-$II$ (Product)
$A$. $RCH_2OH \xrightarrow[(ii) H_3O^{+}]{(i) NaOH, KMnO_4} ?$	$i$. $C_6H_5COOH + C_2H_5OH$
$B$. $CH_3(CH_2)_8CH_2OH \xrightarrow{Jones reagent} ?$	$ii$. $RCOOH$
$C$. $RCONH_2 \xrightarrow{H_3O^{+}, \Delta} ?$	$iii$. $CH_3(CH_2)_8COOH$
$D$. $C_6H_5COOEt \xrightarrow{H_3O^{+}} ?$	$iv$. $RCOOH + NH_3$

Arrange the acidity of the given four compounds in decreasing order:
$(I)$ $CH_3COCH_2COCH_3$
$(II)$ $CH_3COCH_3$
$(III)$ $CH \equiv CH$
$(IV)$ $CH_3CHO$
Select the correct answer from the codes given below:

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Arrange the acidity of the given four compounds in decreasing order:$(I)$ $CH_3COCH_2COCH_3$$(II)$ $CH_3COCH_3$$(III)$ $CH \equiv CH$$(IV)$ $CH_3CHO$Select the correct answer from the codes given below: