Are all the five bonds in $PCl_{5}$ molecule equivalent? Justify your answer.

(N/A) $PCl_{5}$ has a trigonal bipyramidal geometry. In this structure,the three equatorial $P-Cl$ bonds are at $120^{\circ}$ to each other,while the two axial $P-Cl$ bonds are at $90^{\circ}$ to the equatorial plane. Due to greater repulsion from the equatorial bond pairs,the axial bonds are longer and weaker than the equatorial bonds. Therefore,all five bonds in $PCl_{5}$ are not equivalent.