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(A) The electronic configuration $1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^6$ corresponds to the $Ar$ (Argon) noble gas core,which has $18$ electrons.In $Na

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$NaF$

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(A) The electronic configuration $1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^6$ corresponds to the $Ar$ (Argon) noble gas core,which has $18$ electrons.In $NaF$,the ions are $Na^+$ ($10$ electrons: $1s^2 \, 2s^2 \, 2p^6$) and $F^-$ ($10$ electrons: $1s^2 \, 2s^2 \, 2p^6$). Neither ion has the $18$-electron configuration.In $KBr$,$K^+$ ($18$ electrons) and $Br^-$ ($36$ electrons) are present. $K^+$ has the $18$-electron configuration.In $NaCl$,$Cl^-$ ($18$ electrons) is present.In $CaI_2$,$Ca^{2+}$ ($18$ electrons) is present.Therefore,the aqueous solution of $NaF$ does not contain any ions with the $1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^6$ configuration.

Aqueous solution of which salt will not contain ions with the electronic configuration $1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^6$?

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