Aqueous ammonia readily dissolves $AgCl$ because
- A$NH_3$ molecules readily solvate $Ag^{+}$ and $Cl^{-}$ ions
- B$NH_3$ molecules abstract chloride from $AgCl$ to form $NH_4Cl$
- Ca soluble complex $[Ag(NH_3)_6]^{+}$ is formed
- Da soluble complex $[Ag(NH_3)_2]^{+}$ is formed
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Similar Questions
The molar ionic conductance of the octahedral complexes:
$(i)$ $PtCl_4 \cdot 5 NH_3$ $(ii)$ $PtCl_4 \cdot 4 NH_3$ $(iii)$ $PtCl_4 \cdot 3 NH_3$ $(iv)$ $PtCl_4 \cdot 2 NH_3$
Follow the order:
$(i)$ $PtCl_4 \cdot 5 NH_3$ $(ii)$ $PtCl_4 \cdot 4 NH_3$ $(iii)$ $PtCl_4 \cdot 3 NH_3$ $(iv)$ $PtCl_4 \cdot 2 NH_3$
Follow the order:
MediumAIIMS 2019
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Which of the following complexes will be the most stable?
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