Anhydrous aluminium chloride $(Al_2Cl_6)$ is a covalent compound and soluble in water,giving:

  • A
    $Al^{3+}$ and $Cl^{-}$ ions
  • B
    $[Al(H_2O)_6]^{3+}$ and $Cl^{-}$ ions
  • C
    $[AlCl_2(H_2O)_4]^+$ and $[AlCl_4(H_2O)_2]^-$ ions
  • D
    None of the above

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Use the following data to calculate $\Delta _{lattice}H^{\theta }$ for $NaBr$. $\Delta _{sub}H^{\theta }$ for sodium metal $= 108.4 \ kJ \ mol^{-1}$,ionization enthalpy of sodium $= 496 \ kJ \ mol^{-1}$,electron gain enthalpy of bromine $= -325 \ kJ \ mol^{-1}$,bond dissociation enthalpy of bromine $= 192 \ kJ \ mol^{-1}$,$\Delta _{f}H^{\theta }$ for $NaBr_{(s)}$ $= -360.1 \ kJ \ mol^{-1}$.

The correct order of lattice energy of the following compounds is:

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