Angles made by the lines represented by the e | vedclass

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(A) The given equation is $xy + y = 0$. Factoring the equation,we get $y(x + 1) = 0$. This implies the two lines are $y = 0$ and $x = -1$. The line $y

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$0^o$ and $90^o$

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(A) The given equation is $xy + y = 0$. Factoring the equation,we get $y(x + 1) = 0$. This implies the two lines are $y = 0$ and $x = -1$. The line $y = 0$ is the $x$-axis,which is perpendicular to the $y$-axis,so it makes an angle of $90^o$ with the $y$-axis. The line $x = -1$ is a vertical line parallel to the $y$-axis,so it makes an angle of $0^o$ with the $y$-axis. Thus,the angles are $0^o$ and $90^o$.

Angles made by the lines represented by the equation $xy + y = 0$ with the $y$-axis are

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