Angle of dip at a place is $30^o,$ and the horizontal component of earth's field is $5 \times 10^{-5}$ $tesla$, then the vertical component and the total magnetic field at that place is :-
$5 \times 10^{-5} \,T, 10 \times 10^{-5} \,T$
$(5 \times \sqrt 3) \times 10^{-5} \,T, (10/ \sqrt 3) \times 10^{-5} \,T$
$(5 \sqrt 3) \times 10^{-5} \,T, (10/ \sqrt 3) \times 10^{-5} \,T$
None of the above
The magnetic compass is not useful for navigation near the magnetic poles because
A magnetic needle oscillates in a horizontal plane with a period $T$ at a place where the angle of dip is $60^{\circ}$. When the same needle is made to oscillate in a vertical plane coinciding with the magnetic meridian, its period will be
At a certain place the horizontal component of the earth’s magnetic field is $B_0$ and the angle of dip is $45^o$. The total intensity of the field at that place will be
The relations amongst the three elements elements earth's magnettic fleld, namely horizontal component $H$, vertical component $V$ and dip $\delta$ are, $( B_{E}=$ total magnetic fleld)
What is dynamo effect ?