Angle of dip at a place is $30^o,$ and the horizontal component of earth's field is $5 \times 10^{-5}$ $tesla$, then the vertical component and the total magnetic field at that place is :-
$5 \times 10^{-5} \,T, 10 \times 10^{-5} \,T$
$(5 \times \sqrt 3) \times 10^{-5} \,T, (10/ \sqrt 3) \times 10^{-5} \,T$
$(5 \sqrt 3) \times 10^{-5} \,T, (10/ \sqrt 3) \times 10^{-5} \,T$
None of the above
If declination at a place is known to be $15^{\circ} \,E$. And a compass needle points as shown, then geographic north is represented by the direction numbered.
The line on the earth's surface joining the points where the field is horizontal is
Ratio between total intensity of magnetic field at equator to poles is
At a place, the magnitudes of the horizontal component and total intensity of the magnetic field of the earth are $0.3 $ and $ 0.6$ Oersted respectively. The value of the angle of dip at this place will be.....$^o$
The values of the apparent angles of dip in two planes at right angles to each other are $45^{\circ}$ and $30^{\circ}$ respectively. The true value of angle of dip at the place is ............