An unknown chlorohydrocarbon has $3.55\%$ of chlorine. If each molecule of the hydrocarbon has one chlorine atom only,the number of chlorine atoms present in $1\,g$ of chlorohydrocarbon is (Atomic wt. of $Cl = 35.5\,u$; Avogadro constant $= 6.023 \times 10^{23}\,mol^{-1}$)
- A$6.023 \times 10^9$
- B$6.023 \times 10^{23}$
- C$6.023 \times 10^{21}$
- D$6.023 \times 10^{20}$
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