An unbiased coin is tossed thrice. The probab | vedclass

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Question

(B) When an unbiased coin is tossed thrice,the total number of possible outcomes is $2^3 = 8$.These outcomes are: $HHH, HHT, HTH, THH, HTT, THT, TTH,

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$3/8$

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(B) When an unbiased coin is tossed thrice,the total number of possible outcomes is $2^3 = 8$.These outcomes are: $HHH, HHT, HTH, THH, HTT, THT, TTH, TTT$.We are looking for the event of receiving exactly two heads.The favorable outcomes are: $HHT, HTH, THH$.Thus,the number of favorable outcomes is $m = 3$.The probability of an event is given by the ratio of favorable outcomes to total outcomes.Therefore,the required probability $= \frac{m}{n} = \frac{3}{8}$.

An unbiased coin is tossed thrice. The probability of receiving two heads is ..........

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