An organic compound of molecular formula C_6H | vedclass

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(C) The molecular formula is $C_6H_6Br_2$.Double bond equivalent $(DBU)$ formula $= C - \frac{H}{2} - \frac{X}{2} + 1$.For $C=6, H=6, X=2$:$DBU = 6 -

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homo-cyclic but not aromatic

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(C) The molecular formula is $C_6H_6Br_2$.Double bond equivalent $(DBU)$ formula $= C - \frac{H}{2} - \frac{X}{2} + 1$.For $C=6, H=6, X=2$:$DBU = 6 - \frac{6}{2} - \frac{2}{2} + 1 = 6 - 3 - 1 + 1 = 3$.This indicates the presence of one ring and two double bonds.The structure consists of a six-membered carbon ring (homo-cyclic) with two non-conjugated double bonds and two bromo groups at the $1,4$ positions.Since it does not satisfy $H$ückel's rule ($4n+2$ $\pi$ electrons in a planar,fully conjugated system),it is not aromatic.Therefore,the compound is homo-cyclic but not aromatic.

An organic compound of molecular formula $C_6H_6Br_2$ has six carbon atoms in a ring system,two non-conjugate double bonds and two bromo groups at $1,4$ positions. Then the compound is

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