(A) To find the empirical formula,we calculate the molar ratio of each element: $1$. For $C$: $\frac{38.8}{12} = 3.23$ $2$. For $H$: $\frac{16}{1} = 1

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(A) To find the empirical formula,we calculate the molar ratio of each element: $1$. For $C$: $\frac{38.8}{12} = 3.23$ $2$. For $H$: $\frac{16}{1} = 16$ $3$. For $N$: $\frac{45.2}{14} = 3.23$ Dividing by the smallest value $(3.23)$: $C: \frac{3.23}{3.23} = 1$ $H: \frac{16}{3.23} \approx 5$ $N: \frac{3.23}{3.23} = 1$ The empirical formula is $CH_5N$,which can be written as $CH_3NH_2$.

Class 11 Chemistry Some Basic Concepts of Chemistry Percentage composition and Molecular formula

Medium

An organic compound contains $C = 38.8\%$,$H = 16\%$ and $N = 45.2\%$. The empirical formula of the compound is:

A
$CH_3NH_2$
B
$CH_3CN$
C
$C_2H_5CN$
D
$CH_2(NH)_2$

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Some Basic Concepts of Chemistry

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Percentage composition and Molecular formula

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An organic compound contains $C = 38.8\%$,$H = 16\%$ and $N = 45.2\%$. The empirical formula of the compound is:

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An organic compound contains $49.3\%$ carbon,$6.84\%$ hydrogen and its vapour density is $73$. The molecular formula of the compound is:

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