An organic compound C_3H_6O does not give a p | vedclass

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(D) $1$. The molecular formula $C_3H_6O$ corresponds to the degree of unsaturation $U = 3 - (6/2) + 1 = 1$. This indicates the presence of one double

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$CH_2=CH-O-CH_3$

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(D) $1$. The molecular formula $C_3H_6O$ corresponds to the degree of unsaturation $U = 3 - (6/2) + 1 = 1$. This indicates the presence of one double bond or one ring.$2$. The compound does not react with $2,4-$Dinitrophenylhydrazine ($2,4-DNP$), which means it does not contain a carbonyl group (aldehyde or ketone).$3$. The compound does not react with metallic sodium, which means it does not contain an active hydrogen atom (like in alcohols or phenols).$4$. Given the formula $C_3H_6O$, the structure $CH_2=CH-O-CH_3$ (methyl vinyl ether) fits all criteria: it has no carbonyl group, no hydroxyl group, and satisfies the molecular formula.

An organic compound $C_3H_6O$ does not give a precipitate with $2,4-$Dinitrophenylhydrazine reagent and does not react with metallic sodium. The compound is:

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