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(B) $1$. The molecular formula $C_8H_{16}$ corresponds to the general formula $C_nH_{2n}$,which indicates an alkene.$2$. Ozonolysis of an alkene invol

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(B) $1$. The molecular formula $C_8H_{16}$ corresponds to the general formula $C_nH_{2n}$,which indicates an alkene.$2$. Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form carbonyl compounds.$3$. The problem states that one of the products is acetone,which is $CH_3COCH_3$. This implies the original alkene must contain a $(CH_3)_2C=$ group.$4$. The compound must also be optically active,meaning it must contain a chiral center (a carbon atom bonded to four different groups).$5$. Analyzing the options,the structure in option $B$ is $3,4$-dimethylhex-$2$-ene,but specifically,the structure shown is $2,3$-dimethylhex-$2$-ene. Let's re-examine the structure: the compound $2,3$-dimethylhex-$2$-ene has a chiral center at the $C_3$ position,which is bonded to a methyl group,an ethyl group,a hydrogen atom,and the $C=C$ group. Thus,it is optically active.$6$. Ozonolysis of $2,3$-dimethylhex-$2$-ene yields acetone and $2$-methylbutanal. Therefore,the correct structure is the one shown in option $B$.

An optically active compound having molecular formula $C_8H_{16}$ on ozonolysis gives acetone as one of the products. The structure of the compound is

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