An octahedral complex of Co^{3+} is diamagnet | vedclass

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(C) The atomic number of $Co$ is $27$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.Since the complex is octahedral and diamagnetic,the li

Vedclass · Accepted Answer

$d^2sp^3$

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(C) The atomic number of $Co$ is $27$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.Since the complex is octahedral and diamagnetic,the ligands must be strong field ligands that cause pairing of electrons in the $3d$ orbitals.This results in two empty $3d$ orbitals,one $4s$ orbital,and three $4p$ orbitals,which hybridize to form six $d^2sp^3$ hybrid orbitals.Thus,the hybridisation involved is $d^2sp^3$.

An octahedral complex of $Co^{3+}$ is diamagnetic. The hybridisation involved in the formation of the complex is

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