An object of mass 4.237 , g occupies a volume | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given mass $m = 4.237 \, g$ (which has $4$ significant figures).Given volume $V = 1.72 \, cm^3$ (which has $3$ significant figures).Density $\rho

Vedclass · Accepted Answer

$2.46$

Vedclass · Answer

(A) Given mass $m = 4.237 \, g$ (which has $4$ significant figures).Given volume $V = 1.72 \, cm^3$ (which has $3$ significant figures).Density $\rho = \frac{m}{V} = \frac{4.237 \, g}{1.72 \, cm^3} \approx 2.46337 \, g \, cm^{-3}$.According to the rules of significant figures,the result of division should have the same number of significant figures as the measurement with the least number of significant figures.Since $1.72$ has $3$ significant figures,the final answer must be rounded to $3$ significant figures.Therefore,the density is $2.46 \, g \, cm^{-3}$.

An object of mass $4.237 \, g$ occupies a volume of $1.72 \, cm^3$. The density of the object to appropriate significant figures is ......... $g \, cm^{-3}$.

Similar Questions

The decimal equivalent of $\frac{1}{20}$ up to three significant figures is

The volume of a sphere is $1.76 \ cm^3$. The volume of $25$ such spheres,taking into account significant figures,is:

Which of the following measurements is the most accurate?

The radius of a thin wire is $0.16 \; mm$. The area of cross-section taking significant figures into consideration in square millimeters is?

If a calculated value $2.7465 \,g$ contains only three significant figures,the two insignificant digits in it are ............

Vedclass Test Series

Exam Paper Generator

Online Exam Module