An object of mass 1 ,kg travelling in a strai | vedclass

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Question

(D) Mass of the object,$m_1 = 1\, kg$.Velocity of the object before collision,$v_1 = 10\, m/s$.Mass of the stationary wooden block,$m_2 = 5\, kg$.Velo

Vedclass · Accepted Answer

$10\, kg\, m\, s^{-1}$,$5/3\, m/s$

Vedclass · Answer

(D) Mass of the object,$m_1 = 1\, kg$.Velocity of the object before collision,$v_1 = 10\, m/s$.Mass of the stationary wooden block,$m_2 = 5\, kg$.Velocity of the wooden block before collision,$v_2 = 0\, m/s$.Total momentum before collision $= m_1 v_1 + m_2 v_2 = 1(10) + 5(0) = 10\, kg\, m\, s^{-1}$.According to the law of conservation of momentum,the total momentum remains conserved.Therefore,total momentum after collision $= 10\, kg\, m\, s^{-1}$.Total mass of the combined system $= m_1 + m_2 = 1 + 5 = 6\, kg$.Let the velocity of the combined object be $v$.$10 = (m_1 + m_2)v$$10 = 6v$$v = 10/6 = 5/3\, m/s$.

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