(A) In a vacuum,there is no air resistance acting on the objects. According to the equation of motion $h = \frac{1}{2}gt^2$,the time taken to fall fro

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Acceleration due to gravity in vacuum is same irrespective of the size and mass of the body

(A) In a vacuum,there is no air resistance acting on the objects. According to the equation of motion $h = \frac{1}{2}gt^2$,the time taken to fall from a height $h$ is $t = \sqrt{\frac{2h}{g}}$. Since the acceleration due to gravity $g$ is independent of the mass and size of the object,both the iron ball and the wooden ball experience the same acceleration. Therefore,they reach the ground at the same time.

Class 11 Physics Gravitation Acceleration Due to Gravity and its Variation

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An iron ball and a wooden ball of the same radius are released from the same height in vacuum. They take the same time to reach the ground. The reason for this is

A
Acceleration due to gravity in vacuum is same irrespective of the size and mass of the body
B
Acceleration due to gravity in vacuum depends upon the mass of the body
C
There is no acceleration due to gravity in vacuum
D
In vacuum there is a resistance offered to the motion of the body and this resistance depends upon the mass of the body

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Gravitation

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Acceleration Due to Gravity and its Variation

Starting from the centre of the earth having radius $R$,the variation of $g$ (acceleration due to gravity) is shown by:

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$A$ body weighs $250\,N$ on the surface of the earth. How much will it weigh halfway down to the center of the earth (in $,N$)?

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If the radius of the earth is increased by a factor of $5$,by what factor must its density be changed to keep the value of $g$ the same?

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$A$ body weighs $72 \ N$ on the surface of the earth. What is the gravitational force on it at a height equal to half the radius of the earth (in $N$)?

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What is the depth at which the value of acceleration due to gravity becomes $\frac{1}{n}$ times the value at the surface of the Earth? (radius of Earth $= R$)

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An iron ball and a wooden ball of the same radius are released from the same height in vacuum. They take the same time to reach the ground. The reason for this is

Similar Questions

Starting from the centre of the earth having radius $R$,the variation of $g$ (acceleration due to gravity) is shown by:

$A$ body weighs $250\,N$ on the surface of the earth. How much will it weigh halfway down to the center of the earth (in $,N$)?

If the radius of the earth is increased by a factor of $5$,by what factor must its density be changed to keep the value of $g$ the same?

$A$ body weighs $72 \ N$ on the surface of the earth. What is the gravitational force on it at a height equal to half the radius of the earth (in $N$)?

What is the depth at which the value of acceleration due to gravity becomes $\frac{1}{n}$ times the value at the surface of the Earth? (radius of Earth $= R$)

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