An integer is chosen at random and squared. The probability that the last digit of the square is $1$ or $5$ is

  • A
    $\frac{2}{10}$
  • B
    $\frac{3}{10}$
  • C
    $\frac{4}{10}$
  • D
    $\frac{9}{25}$

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Let $A$ and $B$ be two events such that $P(\overline{A \cup B}) = \frac{1}{6}$,$P(A \cap B) = \frac{1}{4}$,and $P(\bar{A}) = \frac{1}{4}$,where $\bar{A}$ stands for the complement of event $A$. Then events $A$ and $B$ are

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