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(B) In an $LR$ series circuit,the impedance $Z$ is given by $Z = \sqrt{R^2 + X_L^2}$,where $X_L = \omega L$.Thus,$Z = \sqrt{R^2 + \omega^2 L^2}$.The c

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$\frac{V^2 R}{R^2 + \omega^2 L^2}$

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(B) In an $LR$ series circuit,the impedance $Z$ is given by $Z = \sqrt{R^2 + X_L^2}$,where $X_L = \omega L$.Thus,$Z = \sqrt{R^2 + \omega^2 L^2}$.The current $I$ in the circuit is given by $I = \frac{V}{Z} = \frac{V}{\sqrt{R^2 + \omega^2 L^2}}$.The power dissipated in the circuit is given by $P = I^2 R$.Substituting the value of $I$,we get $P = \left( \frac{V}{\sqrt{R^2 + \omega^2 L^2}} \right)^2 R$.Therefore,$P = \frac{V^2 R}{R^2 + \omega^2 L^2}$.

An inductor of inductance $L$ and a resistor of resistance $R$ are joined in series and connected to a source of frequency $\omega$. The power dissipated in the circuit is

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