An Indian submarine (I) and an enemy submarin | vedclass

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Question

(A) $1$. First,the enemy submarine acts as a receiver moving towards the source (Indian submarine). The frequency $f'$ received by the enemy submarine

Vedclass · Accepted Answer

$1.02$

Vedclass · Answer

(A) $1$. First,the enemy submarine acts as a receiver moving towards the source (Indian submarine). The frequency $f'$ received by the enemy submarine is: $f' = f \left( \frac{v + v_E}{v} ight) = 1000 \left( \frac{5500 + 70}{5500} ight) \approx 1012.73 \ Hz$.$2$. The enemy submarine then acts as a source reflecting this frequency back to the Indian submarine. The Indian submarine is moving towards this source. The frequency $f''$ detected by the Indian submarine is: $f'' = f' \left( \frac{v + v_I}{v} ight) = 1012.73 \left( \frac{5500 + 50}{5500} ight) \approx 1012.73 	imes 1.00909 \approx 1021.94 \ Hz$.$3$. Converting to $kHz$,we get $f'' \approx 1.02 \ kHz$.

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