An ideal transformer converts $220 V$ $AC$ to $3.3 kV$ $AC$. It transmits the power of $4.4 kW$. If the primary coil has $600$ turns,then the alternating current in the secondary coil is

  • A
    $\frac{1}{3} A$
  • B
    $\frac{4}{3} A$
  • C
    $\frac{5}{3} A$
  • D
    $\frac{7}{3} A$

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