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(B) The coefficient of performance $(COP)$,$\beta$,for an ideal refrigerator is given by the formula: $\beta = \frac{T_2}{T_1 - T_2}$,where $T_2$ is t

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$39^{\circ} C$

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(B) The coefficient of performance $(COP)$,$\beta$,for an ideal refrigerator is given by the formula: $\beta = \frac{T_2}{T_1 - T_2}$,where $T_2$ is the temperature of the freezer and $T_1$ is the temperature of the surroundings (sink).Given: $\beta = 5$ and $T_2 = -13^{\circ} C = (-13 + 273) K = 260 K$.Substituting the values into the formula:$5 = \frac{260}{T_1 - 260}$$5(T_1 - 260) = 260$$5T_1 - 1300 = 260$$5T_1 = 1560$$T_1 = 312 K$Converting back to Celsius: $T_1 = (312 - 273)^{\circ} C = 39^{\circ} C$.

An ideal refrigerator has a freezer at a temperature of $-13^{\circ} C$. The coefficient of performance of the refrigerator is $5$. The temperature of the air (to which heat is rejected) is:

Similar Questions

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The coefficient of performance of a refrigerator is $5$. If the temperature inside the freezer is $-20^{\circ}C$,the temperature of the surroundings to which it rejects heat is ........ $^{\circ}C$.

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