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(D) The internal energy $U$ of an ideal gas is given by the formula $U = \frac{f}{2} nRT$,where $f$ is the degree of freedom.Using the ideal gas equat

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(D) The internal energy $U$ of an ideal gas is given by the formula $U = \frac{f}{2} nRT$,where $f$ is the degree of freedom.Using the ideal gas equation $PV = nRT$,we can substitute $nRT$ with $PV$ to get $U = \frac{f}{2} PV$.Given $P = 3	imes10^6\, Pa$ and $V = 2\, m^3$,the product $PV = 6	imes10^6\, J$.Since the degree of freedom $f$ depends on the nature of the gas (monatomic,diatomic,etc.) and is not provided in the question,the internal energy cannot be uniquely determined.Therefore,the information provided is insufficient.

An ideal gas occupies a volume of $2\, m^3$ at a pressure of $3\times10^6\, Pa$. The energy of the gas is

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