An ideal gas is compressed from 10 dm^3 to 1 | vedclass

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(C) The work done during the compression of a gas at constant pressure is given by the formula: $W = -P_{ext} 	imes \Delta V$. Here, $P_{ext} = 2 \ b

Vedclass · Accepted Answer

$1.8$

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(C) The work done during the compression of a gas at constant pressure is given by the formula: $W = -P_{ext} 	imes \Delta V$. Here, $P_{ext} = 2 \ bar$, $V_1 = 10 \ dm^3$, and $V_2 = 1 \ dm^3$. $\Delta V = V_2 - V_1 = 1 \ dm^3 - 10 \ dm^3 = -9 \ dm^3$. $W = -2 \ bar 	imes (-9 \ dm^3) = +18 \ bar \ dm^3$. Since $1 \ bar \ dm^3 = 100 \ J$, then $18 \ bar \ dm^3 = 1800 \ J = 1.8 \ kJ$. Since the work is done on the gas, the value is positive.

An ideal gas is compressed from $10 \ dm^3$ to $1 \ dm^3$ at a constant pressure of $2 \ bar$. Calculate the work done on the gas during compression. (in $kJ$)

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