An ideal gas expands isothermally along ab an | vedclass

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(B) For an isothermal process,the temperature remains constant,so the change in internal energy $dU = 0$.According to the first law of thermodynamics,

Vedclass · Accepted Answer

the heat absorbed by the gas from the surrounding is $600\,J$

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(B) For an isothermal process,the temperature remains constant,so the change in internal energy $dU = 0$.According to the first law of thermodynamics,$dQ = dU + dW$.Given that the gas does $600\,J$ of work,$dW = 600\,J$.Substituting these values,$dQ = 0 + 600\,J = 600\,J$.Since $dQ$ is positive,the gas absorbs $600\,J$ of heat from the surroundings.

An ideal gas expands isothermally along $ab$ and does $600\,J$ of work. During the process,

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