An ideal gas at pressure $p$ is adiabatically compressed so that its density becomes twice that of the initial. If $\gamma = \frac{c_p}{c_v} = \frac{7}{5}$,then the final pressure of the gas is:

  • A
    $p$
  • B
    $2p$
  • C
    $\frac{7}{5}p$
  • D
    $2.63p$

Explore More

Similar Questions

What is the change in temperature when work is done by a gas in an adiabatic process?

$A$ gas is kept in a container having walls which are thermally non-conducting. Initially,the gas has a volume of $800 \ cm^3$ and a temperature of $27^{\circ} C$. The change in temperature when the gas is adiabatically compressed to $200 \ cm^3$ is ......... $K$. (Take $\gamma=1.5$,where $\gamma$ is the ratio of specific heats at constant pressure and at constant volume.)

One mole of helium is adiabatically expanded from its initial state $({P_i}, {V_i}, {T_i})$ to its final state $({P_f}, {V_f}, {T_f})$. The decrease in the internal energy associated with this expansion is equal to

$A$ triatomic gas at an initial temperature of $18^{\circ}C$ is compressed adiabatically to $1/8$ of its initial volume. What is the final temperature of the gas?

Difficult
View Solution

$A$ gas has pressure $P$ and volume $V$. If the gas is compressed adiabatically to $\frac{1}{32}$ of its initial volume,what will be the new pressure? (Given: $(32)^{1.4} = 128$)

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo