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(A) The input voltage $V_{	ext{in}}$ varies sinusoidally between $+25\ V$ and $-25\ V$.$1$. Positive half cycle $(V_{	ext{in}} > 10\ V)$: The diode

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$10\ V, -25\ V$

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(A) The input voltage $V_{	ext{in}}$ varies sinusoidally between $+25\ V$ and $-25\ V$.$1$. Positive half cycle $(V_{	ext{in}} > 10\ V)$: The diode is forward-biased when $V_{	ext{in}} > 10\ V$. Since the diode is ideal,it acts as a short circuit. The output voltage is clamped by the battery $V = 10\ V$. Thus,$V_{	ext{out}} = 10\ V$.$2$. Negative half cycle $(V_{	ext{in}} The maximum value of the output voltage is $10\ V$ (clamped).The minimum value of the output voltage is the minimum input voltage,which is $-25\ V$.Therefore,the maximum and minimum values are $10\ V$ and $-25\ V$ respectively.

List-$I$	List-$II$
$(a)$ Rectifier	$(i)$ Used for stepping up or stepping down the $\text{A.C.}$ voltage
$(b)$ Stabilizer	$(ii)$ Used to convert $\text{A.C.}$ voltage into $\text{D.C.}$ voltage
$(c)$ Transformer	$(iii)$ Used to remove any ripple in the rectified output voltage
$(d)$ Filter	$(iv)$ Used for constant output voltage

An ideal diode is connected in a circuit with resistance $R = 50\ \Omega$ and battery $V = 10\ V$ as shown in the figure. What are the maximum and minimum values of the output voltage when no load is applied?

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