An ideal coil of $10 \ H$ is connected in series with a resistance of $5 \ \Omega$ and a battery of $5 \ V$. $2 \ s$ after the connection is made,the current flowing in the circuit in amperes is:
- A$e^{-1}$
- B$(1 - e^{-1})$
- C$(1 - e)$
- D$e$
Explore More
Similar Questions
An ideal coil of $10 \, H$ is joined in series with a resistance of $5 \, \Omega$ and a battery of $5 \, V$. $2 \, s$ after joining, the current flowing in the circuit in amperes will be:
Medium
View SolutionFind the current in the $4 \Omega$ resistance shown in the figure in the following cases:
$(a)$ Just after the closing of the key.
$(b)$ $A$ long time after the closing of the key.
$(a)$ Just after the closing of the key.
$(b)$ $A$ long time after the closing of the key.
Medium
View Solution$A$ constant voltage of $25 \, V$ is applied to a series $L-R$ circuit at $t=0$ by closing a switch. What is the potential difference across the resistor and the inductor at time $t=0$?
In the circuit shown below,the switch is closed at time $t=0$. Which of the graphs shown below best represents the voltage across the inductor,as seen on an oscilloscope?
DifficultKVPY 2011
View SolutionIn the circuit shown in the figure, what is the value of $I_1$ just after pressing the key $K$?
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo