An engineering student has to secure 25 % mar | vedclass

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Question

(B) To pass the examination,a student needs to secure $25 \%$ of the maximum marks.Given that the student obtained $47$ marks and failed by $43$ marks

Vedclass · Accepted Answer

$360$

Vedclass · Answer

(B) To pass the examination,a student needs to secure $25 \%$ of the maximum marks.Given that the student obtained $47$ marks and failed by $43$ marks,the passing marks can be calculated as:$	ext{Passing Marks} = 47 + 43 = 90$.Since $25 \%$ of the maximum marks is equal to $90$,we can set up the equation:$0.25 	imes 	ext{Maximum Marks} = 90$.$	ext{Maximum Marks} = \frac{90}{0.25} = 90 	imes 4 = 360$.Therefore,the maximum marks of the examination are $360$.

An engineering student has to secure $25 \%$ marks to pass. He gets $47$ marks and fails by $43$ marks. What are the maximum marks of the examination?

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