An engine develops $10 \text{ kW}$ of power. How much time will it take to lift a mass of $200 \text{ kg}$ to a height of $40 \text{ m}$? $(g = 10 \text{ m/s}^2)$

$A$ body of mass $m$ starts from rest and is accelerated uniformly to a velocity $v_1$ in time $t_1$. The instantaneous power delivered to the body as a function of time $t$ is:

$A$ body is moving unidirectionally under the influence of a source of constant power. Its displacement in time $t$ is proportional to

$A$ body is moving uni-directionally under the influence of a source of constant power. Its displacement in time $t$ is proportional to

$A$ particle of mass $0.2 \ kg$ is moving in one dimension under a force that delivers a constant power $0.5 \ W$ to the particle. If the initial speed of the particle is zero,the speed (in $m/s$) after $5 \ s$ is:

$A$ particle moves with a velocity $\vec v = 6\hat i - 4\hat j + 3\hat k \, m/s$ under the influence of a constant force $\vec F = 20\hat i + 15\hat j - 5\hat k \, N$. The instantaneous power applied to the particle is ......... $J/s$.