An elevator of mass $m$ is connected to a rope which pulls the elevator up with a maximum acceleration equal to $a$. If the maximum bearable tension in the rope is $T$,then for a safe journey the minimum diameter of the rope is $[g=$ acceleration due to gravity$]$

  • A
    $[\frac{2 m(g+a)}{\pi T}]^{1/2}$
  • B
    $[\frac{4 m(g+a)}{\pi T}]^{1/2}$
  • C
    $[\frac{m(g+a)}{\pi T}]^{1/2}$
  • D
    $[\frac{m(g+a)}{2 \pi T}]^{1/2}$

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