An elevator in a building can carry a maximum | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The total mass of the persons is $M_p = 10 	imes 68 \; kg = 680 \; kg$.The total mass of the elevator system is $M = M_p + M_{elevator} = 680 \;

Vedclass · Accepted Answer

$66000$

Vedclass · Answer

(C) The total mass of the persons is $M_p = 10 	imes 68 \; kg = 680 \; kg$.The total mass of the elevator system is $M = M_p + M_{elevator} = 680 \; kg + 920 \; kg = 1600 \; kg$.The total downward force due to gravity is $F_g = M 	imes g = 1600 \; kg 	imes 10 \; m/s^{2} = 16000 \; N$.The frictional force opposing the upward motion is $f = 6000 \; N$.Since the elevator moves with a constant speed,the acceleration is zero. Therefore,the tension $T$ in the cable must balance the total downward force:$T = F_g + f = 16000 \; N + 6000 \; N = 22000 \; N$.The power $P$ delivered by the motor is given by $P = T 	imes v$,where $v$ is the velocity.$P = 22000 \; N 	imes 3 \; m/s = 66000 \; W$.

Similar Questions

An engine pumps $100 \ kg$ of water to a height of $10 \ m$ in $5 \ s$. If the efficiency of the engine is $60\%$,the power of the engine is........$kW$. (Take $g = 10 \ m/s^2$.)

Power supplied to a particle of mass $2\, kg$ varies with time as $P = \frac{3t^2}{2} \, W$. Here,$t$ is in $s$. If the velocity of the particle at $t = 0$ is $v = 0$,the velocity of the particle at time $t = 2\, s$ will be ............ $m/s$.

The power of a pump,which can pump $200 \ kg$ of water to a height of $50 \ m$ in $10 \ s$,will be:

$A$ body of mass '$M$' is moving with a uniform speed of '$v$' on a frictionless horizontal surface under the influence of two forces $F_1$ and $F_2$ as shown in the figure. The net power of the system is

$A$ man of mass $80 \ kg$ climbs a ladder of height $6 \ m$ in $10 \ s$. What is the average power generated by him in $HP$ (Horsepower)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module