An element in +2 oxidation state has 24 elect | vedclass

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(B) The electronic configuration of an element with atomic number $Z$ in $+2$ oxidation state is equivalent to an atom with $Z-2$ electrons.Given $Z-2

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$26$ and $4$

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(B) The electronic configuration of an element with atomic number $Z$ in $+2$ oxidation state is equivalent to an atom with $Z-2$ electrons.Given $Z-2 = 24$,the atomic number $Z = 26$. The element is $Fe$.The ground state electronic configuration of $Fe$ $(Z=26)$ is $[Ar] 3d^6 4s^2$.The configuration of $Fe^{2+}$ is $[Ar] 3d^6$.In the $3d^6$ configuration,the electrons are distributed in $5$ orbitals of $d$-subshell according to Hund's rule: $d_{xy}^2, d_{yz}^1, d_{zx}^1, d_{x^2-y^2}^1, d_{z^2}^1$.Thus,there are $4$ unpaired electrons.

An element in $+2$ oxidation state has $24$ electrons. The atomic number of the element and the number of unpaired electrons in it respectively are

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