(B) The total number of electron exchanges is given by the formula $\frac{n(n-1)}{2}$,where $n$ is the number of electrons with the same spin in the s

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(B) The total number of electron exchanges is given by the formula $\frac{n(n-1)}{2}$,where $n$ is the number of electrons with the same spin in the same subshell.For a $d^5$ configuration,all $5$ electrons have the same spin (parallel spin) in $5$ different orbitals.Substituting $n = 5$ into the formula:$\text{Total exchanges} = \frac{5(5-1)}{2} = \frac{5 \times 4}{2} = \frac{20}{2} = 10$.

Class 11 Chemistry Structure of Atom Quantum number, Electronic configuration and Shape of orbitals

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An element has $d^5$ configuration. The total number of electron exchanges possible for it is

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$18$
B
$10$
C
$12$
D
$15$

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Structure of Atom

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Quantum number, Electronic configuration and Shape of orbitals

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An element has $d^5$ configuration. The total number of electron exchanges possible for it is

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What is the maximum number of electrons that can be accommodated in a single $p$ orbital?

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