An electron is travelling along the x-directi | vedclass

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(B) The magnetic force on a moving charge is given by $\overrightarrow{F} = q(\overrightarrow{v} 	imes \overrightarrow{B})$.For an electron,$q = -e$.

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$A$ circle in the $xz$-plane

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(B) The magnetic force on a moving charge is given by $\overrightarrow{F} = q(\overrightarrow{v} 	imes \overrightarrow{B})$.For an electron,$q = -e$. The velocity is $\overrightarrow{v} = v\hat{i}$ and the magnetic field is $\overrightarrow{B} = B\hat{j}$.Substituting these values,we get $\overrightarrow{F} = -e(v\hat{i} 	imes B\hat{j}) = -evB(\hat{i} 	imes \hat{j}) = -evB\hat{k}$.Since the force is always perpendicular to both the velocity and the magnetic field,and the force is directed along the negative $z$-axis,the electron will experience a centripetal force that causes it to move in a circular path in the $xz$-plane.

An electron is travelling along the $x$-direction. It encounters a magnetic field in the $y$-direction. Its subsequent motion will be

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