Medium
An electron is in one of the $3d$ orbitals. Give the possible values of $n$,$l$,and $m$ for this electron.
(N/A) For the $3d$ orbital:
Principal quantum number $(n) = 3$
Azimuthal quantum number $(l) = 2$
Magnetic quantum number $(m) = -2, -1, 0, 1, 2$
Principal quantum number $(n) = 3$
Azimuthal quantum number $(l) = 2$
Magnetic quantum number $(m) = -2, -1, 0, 1, 2$
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Similar Questions
Consider the following sets of quantum numbers:
$Set$ $(n)-(l)-(m)-(s)$ $(i)$ $(3)-(2)-(1)-(+1/2)$ $(ii)$ $(2)-(2)-(1)-(+1/2)$ $(iii)$ $(4)-(3)-(-2)-(-1/2)$ $(iv)$ $(1)-(0)-(-1)-(-1/2)$ $(v)$ $(3)-(2)-(3)-(+1/2)$
Which of the following sets of quantum numbers is not possible?
| $Set$ | $(n)-(l)-(m)-(s)$ |
| $(i)$ | $(3)-(2)-(1)-(+1/2)$ |
| $(ii)$ | $(2)-(2)-(1)-(+1/2)$ |
| $(iii)$ | $(4)-(3)-(-2)-(-1/2)$ |
| $(iv)$ | $(1)-(0)-(-1)-(-1/2)$ |
| $(v)$ | $(3)-(2)-(3)-(+1/2)$ |
Which of the following sets of quantum numbers is not possible?
MediumAIPMT 2007
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Principal quantum number $(n)$ Azimuthal quantum number $(l)$ Magnetic quantum number $(m)$
| Principal quantum number $(n)$ | Azimuthal quantum number $(l)$ | Magnetic quantum number $(m)$ |
|---|
Medium
View SolutionIf $n = 3$,then which of the following values of $l$ is incorrect?
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View SolutionThe state of an electron in a $3d_{z^2}$ orbital is described by which quantum numbers?
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