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(A) According to Bohr's postulate,the angular momentum $L$ of an electron in the $n^{th}$ orbit is given by $L = \frac{nh}{2\pi}$.Given that the elect

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$2.11 	imes 10^{-34} \ J \cdot s$

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(A) According to Bohr's postulate,the angular momentum $L$ of an electron in the $n^{th}$ orbit is given by $L = \frac{nh}{2\pi}$.Given that the electron excites from the $n_1 = 2$ orbit to the $n_2 = 4$ orbit.The change in angular momentum $\Delta L$ is given by:$\Delta L = L_2 - L_1 = \frac{n_2 h}{2\pi} - \frac{n_1 h}{2\pi} = \frac{h}{2\pi} (n_2 - n_1)$.Substituting the values:$\Delta L = \frac{6.64 	imes 10^{-34}}{2 	imes 3.14} (4 - 2)$.$\Delta L = \frac{6.64 	imes 10^{-34}}{6.28} 	imes 2$.$\Delta L = 1.0576 	imes 10^{-34} 	imes 2 \approx 2.11 	imes 10^{-34} \ J \cdot s$.

An electron in the hydrogen atom excites from the $2^{nd}$ orbit to the $4^{th}$ orbit. The change in angular momentum of the electron is (Planck's constant $h = 6.64 \times 10^{-34} \ J \cdot s$).

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