An electron has a mass of 9.1 times 10^{-31} | vedclass

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(B) The linear momentum $p$ of an object is given by the product of its mass $m$ and its velocity $v$.$p = m 	imes v$Given:Mass $m = 9.1 	imes 10^{-

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$2.0 	imes 10^{-24} \ kg \cdot m/s$

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(B) The linear momentum $p$ of an object is given by the product of its mass $m$ and its velocity $v$.$p = m 	imes v$Given:Mass $m = 9.1 	imes 10^{-31} \ kg$Velocity $v = 2.2 	imes 10^6 \ m/s$Substituting these values into the formula:$p = (9.1 	imes 10^{-31} \ kg) 	imes (2.2 	imes 10^6 \ m/s)$$p = (9.1 	imes 2.2) 	imes 10^{-31+6} \ kg \cdot m/s$$p = 20.02 	imes 10^{-25} \ kg \cdot m/s$$p = 2.002 	imes 10^{-24} \ kg \cdot m/s$Rounding to two significant figures,we get:$p \approx 2.0 	imes 10^{-24} \ kg \cdot m/s$Thus,the correct option is $B$.

An electron has a mass of $9.1 \times 10^{-31} \ kg$. It revolves around the nucleus in a circular orbit of radius $0.529 \times 10^{-10} \ m$ at a speed of $2.2 \times 10^6 \ m/s$. The magnitude of its linear momentum in this motion is:

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