An electron collides with an atom in its grou | vedclass

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(A) Let $K_i$ be the initial kinetic energy of the electron and $K_f$ be its final kinetic energy after the collision.According to the law of conserva

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Greater than $E_{photon}$

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(A) Let $K_i$ be the initial kinetic energy of the electron and $K_f$ be its final kinetic energy after the collision.According to the law of conservation of energy,the initial energy of the system must equal the final energy of the system.$K_i = K_f + E_{photon} + K_{atom}$,where $K_{atom}$ is the kinetic energy gained by the atom due to the recoil effect.Rearranging the terms,we get the change in the electron's energy as $\Delta E_{elec} = K_i - K_f = E_{photon} + K_{atom}$.Since the atom must recoil to conserve momentum,$K_{atom} > 0$.Therefore,$\Delta E_{elec} > E_{photon}$.

An electron collides with an atom in its ground state. The atom then emits a photon of energy $E_{photon}$. In this process,the change $\Delta E_{elec}$ in the electron's energy is

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