An electric kettle of $2 kW$ -works for $2 h$ daily. Calculate the $(a)$ energy consumed in $SI$ and commercial units $(b)$ cost of running it in the month of June at the rate of ₹ $3.00$ per unit.
An electric kettle of $2 kW$ -works for $2 h$ daily. Calculate the $(a)$ energy consumed in $SI$ and commercial units $(b)$ cost of running it in the month of June at the rate of ₹ $3.00$ per unit.
$(a)$ Here, power, $P =2 kW =2000 W ,$ time, $t=2 h$ Energy, $E = P \times t=2000 W \times 2 h =4 kWh$
$(b)$ Total energy consumed in June
$=4 \times 30 kWh$
$=120 kWh$
$\therefore$ Total $\cos t=120 \times 3.00=$₹ $360$
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