An electric iron has a rating of $750\, W; 200\, V$. Calculate:
$(i)$ The current required.
$(ii)$ The resistance of its heating element.
$(iii)$ Energy consumed by the iron in $2$ hours.

(N/A) $(i)$ Current $(I)$ is calculated using the formula $P = V \times I$,so $I = P / V = 750\, W / 200\, V = 3.75\, A$.
$(ii)$ Resistance $(R)$ is calculated using Ohm's Law $V = I \times R$,so $R = V / I = 200\, V / 3.75\, A \approx 53.33\, \Omega$.
$(iii)$ Energy consumed $(E)$ is calculated as $E = P \times t = 750\, W \times 2\, h = 1500\, Wh = 1.5\, kWh$.