An electric iron has a rating of $750\, W ; 200\, V$. Calculate
$(i)$ the current required.
$(ii)$ the resistance of its heating element.
$(iii)$ energy consumed by the iron in $2$ hours.
An electric iron has a rating of $750\, W ; 200\, V$. Calculate
$(i)$ the current required.
$(ii)$ the resistance of its heating element.
$(iii)$ energy consumed by the iron in $2$ hours.
$(i)$ Current required $=\frac{750 W }{200 V }=3.75 A$
$(ii)$ Resistance $=\frac{200 V }{3.75 A }=53.3 V$
$(iii)$ Energy.consumed $=750 W \times 2 h =1500 Wh$
$=1.5\, kWh$
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