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(A) According to Gauss's law,the electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{enclosed}}{\epsilon_0}$.Since an electric

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The flux of the electric field through the sphere is zero.

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(A) According to Gauss's law,the electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{enclosed}}{\epsilon_0}$.Since an electric dipole consists of two equal and opposite charges ($+q$ and $-q$),the net charge enclosed by the sphere is $q_{net} = +q + (-q) = 0$.Therefore,the net electric flux through the sphere is $\phi = \frac{0}{\epsilon_0} = 0$.However,the electric field at any point on the sphere is the vector sum of the fields produced by the individual charges of the dipole,which is not zero at every point.Similarly,the electric potential is not zero everywhere on the sphere,except for the equatorial plane of the dipole.

An electric dipole is placed at the centre of a sphere. Mark the correct answer.

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