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(C) In a uniform electric field,the force on a dipole is given by $\vec{F} = q\vec{E} + (-q)\vec{E} = 0$. Since the dipole moment $\vec{p}$ is along t

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Zero and minimum

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(C) In a uniform electric field,the force on a dipole is given by $\vec{F} = q\vec{E} + (-q)\vec{E} = 0$. Since the dipole moment $\vec{p}$ is along the direction of the electric field $\vec{E}$,the angle $	heta$ between them is $0^\circ$. The potential energy $U$ of an electric dipole in an external electric field is given by $U = -\vec{p} \cdot \vec{E} = -pE \cos 	heta$. Substituting $	heta = 0^\circ$,we get $U = -pE \cos(0^\circ) = -pE$. Since $-pE$ is the lowest possible value for the potential energy,it is the minimum potential energy. Therefore,the force is zero and the potential energy is minimum.

An electric dipole has the magnitude of its charge as $q$ and its dipole moment is $p$. It is placed in a uniform electric field $E$. If its dipole moment is along the direction of the field,the force on it and its potential energy are respectively

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