An automobile driver travels from a plane to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The average speed is defined as the total distance divided by the total time taken.Total distance $D = 120 \ km + 120 \ km + 120 \ km = 360 \ km$.

Vedclass · Accepted Answer

$\frac{3}{\frac{1}{30} + \frac{1}{25} + \frac{1}{50}} \ km/hr$

Vedclass · Answer

(C) The average speed is defined as the total distance divided by the total time taken.Total distance $D = 120 \ km + 120 \ km + 120 \ km = 360 \ km$.Time taken for the first leg $t_1 = \frac{120}{30} = 4 \ hr$.Time taken for the return trip $t_2 = \frac{120}{25} = 4.8 \ hr$.Time taken for the final leg $t_3 = \frac{120}{50} = 2.4 \ hr$.Total time $T = t_1 + t_2 + t_3 = \frac{120}{30} + \frac{120}{25} + \frac{120}{50} \ hr$.Average speed $v_{avg} = \frac{D}{T} = \frac{120 + 120 + 120}{\frac{120}{30} + \frac{120}{25} + \frac{120}{50}}$.Dividing numerator and denominator by $120$,we get $v_{avg} = \frac{3}{\frac{1}{30} + \frac{1}{25} + \frac{1}{50}} \ km/hr$.

Similar Questions

The harmonic mean of $4, 8, 16$ is

If $\log_a x, \log_b x, \log_c x$ are in $H.P.$,then $a, b, c$ are in

If the roots of the equation $k x^3 - 18 x^2 - 36 x + 8 = 0$ are in harmonic progression,then $k =$

If $p, q, r$ are in harmonic progression and $p$ and $r$ are distinct and have the same sign,then what is the nature of the roots of the equation $px^2 + 2qx + r = 0$?

If $X = \sum_{n=0}^\infty a^n$,$Y = \sum_{n=0}^\infty b^n$,and $Z = \sum_{n=0}^\infty c^n$,where $a, b, c$ are in arithmetic progression and $|a| < 1, |b| < 1, |c| < 1$,then $X, Y, Z$ are in:

Vedclass Test Series

Exam Paper Generator

Online Exam Module