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(B) The power delivered by the reactor is $P = 300 \, MW = 300 	imes 10^6 \, J/s$.The energy released per fission is $E = 170 \, MeV = 170 	imes 10^

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$4 	imes 10^{22}$

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(B) The power delivered by the reactor is $P = 300 \, MW = 300 	imes 10^6 \, J/s$.The energy released per fission is $E = 170 \, MeV = 170 	imes 10^6 	imes 1.6 	imes 10^{-19} \, J$.The number of fissions per second is given by $n/t = P/E$.$n/t = (300 	imes 10^6) / (170 	imes 10^6 	imes 1.6 	imes 10^{-19}) \approx 1.103 	imes 10^{19} \, 	ext{atoms/s}$.To find the number of atoms fissioned per hour, we multiply by $3600 \, s$:$N = (1.103 	imes 10^{19}) 	imes 3600 \approx 3.97 	imes 10^{22} \approx 4 	imes 10^{22} \, 	ext{atoms/hour}$.

An atomic power nuclear reactor can deliver $300 \, MW$. The energy released due to fission of each nucleus of uranium atom $U^{238}$ is $170 \, MeV$. The number of uranium atoms fissioned per hour will be

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