An atom of an element A has three electrons i | vedclass

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(B) The valency of an element is determined by the number of electrons it needs to gain or lose to complete its octet.Element $A$ has $3$ valence elec

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$A_2B_3$

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(B) The valency of an element is determined by the number of electrons it needs to gain or lose to complete its octet.Element $A$ has $3$ valence electrons,so it loses $3$ electrons to achieve a stable configuration. Thus,its valency is $3$.Element $B$ has $6$ valence electrons,so it needs to gain $2$ electrons to complete its octet. Thus,its valency is $2$.Using the criss-cross method,the formula of the compound formed by $A$ (valency $3$) and $B$ (valency $2$) is $A_2B_3$.

An atom of an element $A$ has three electrons in its outermost shell and that of $B$ has six electrons in the outermost shell. The formula of the compound between these two will be

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